At constant temperature & volume, 50% of ozone is decomposed out of 2 atm of ozone taken initially and the equilibrium is established, Kp for the decomposition of ozone is
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Detailed Solution
Initial pressure of O3 = 2 atmdegree of decomposition =Decrease in pressure due to decomposition of O3 = 0.5 x 2= 1 atm2 moles of O3 → 3 moles of O21 moles of O3 → 'x' moles of O2Number of molesα partial pressure
At constant temperature & volume, 50% of ozone is decomposed out of 2 atm of ozone taken initially and the equilibrium is established, Kp for the decomposition of ozone is