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In the conversion of alkyne to trans-alkene by Birch reduction using alkali metals (such as Na or K) in liquid NH3 and alcohol (MeOH or EtOH),

the mechanism takes place in the formation of intermediate species in the following sequence:

 

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a
Radical anion → vinylic radical → trans-vinylic dianion → trans-alkene
b
Radical anion → trans-vinylic anion → vinylic radical → trans-alkene
c
Vinylic radical → radical anion → trans-vinylic anion → trans-alkene
d
Vinvlic radical → trans-vinylic anion → radical anion → trans-alkene
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detailed solution

Correct option is A

The sodium metal donates electrons and anion is formed. The dianion formed is stable if the negative charges is opposite side.


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Ethyne reacts with ammonium chloride in the presence of cuprous chloride. The sum of π-bonds present in product molecule  will be 

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