Q.
The conversion of A→B follows second-order kinetics. Doubling the concentration of A will increase the rate of formation of B by a factor
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a
1/4
b
2
c
1/2
d
4
answer is D.
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Detailed Solution
r=k(A)2, when concentration is doubledr=k(2A)2=k4(A)2 the rate becomes 4 times.