The correct arrangement of decreasing order of atomic radius among Na, K, Mg and Rb is
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a
Rb > Na > K > M
b
K > Rb > Na > Mg
c
Rb > K > Na > Mg
d
Mg > Rb > K > Na
answer is C.
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Detailed Solution
Na, K and Rb are of group I elements and size increase downthe group 1 elements (↓).Na and Mg are of group 1 and 2 elements respectively but both belong to 3rd period. Along the period size decreases (↓), i.e. size of Na > Mg.Hence the order of sizes is