The correct increasing order of basic strength of the labeled N is:
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a
I < II < III < IV
b
I < II < IV< III
c
I < III < IV < II
d
IV < III < II < I
answer is B.
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Detailed Solution
III is most basic nitrogen because protonation here produces resonance stabilized conjugate acid.I is least basic as lone pair of nitrogen is delocalized over two carbonyl groups. II is less basic than IV because lone pair of nitrogen II is more delocalized, less available for donation.