The correct order of basicities of the following compounds is:
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a
b
CH3-CH2-NH2
c
CH32NH,
d
answer is B.
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Detailed Solution
(1) > (3) > (2) > (4).(1) More basic due to the presence of two LP e¯ on each N.(2) EtNH2. Due to + I effect of (Et) group, but +I effect of two Me groups is greater than +I effect of (Et) group. Hence, (3)is more basic than (2).(3) (CH3)2NH. Due to (+I) effect of two Me groups.(4) (Amides are resonance stabilised; so they are the weakest bases. Amides behave as amphoteric.)