First slide

Chemical properties

Question

Correct order of bond angles are in

Difficult

A

$H_{2} O > {OF}_{2} > {Cl}_{2} O > {ClO}_{2}$
B

${OF}_{2} > H_{2} O > {Cl}_{2} O > {ClO}_{2}$
C

${ClO}_{2} > {Cl}_{2} O > H_{2} O > {OF}_{2}$
D

${OF}_{2} > {OCl}_{2} > H_{2} O > {ClO}_{2}$

Solution

In ${ClO}_{2}$ , due to larger size of chlorine atom, repulsion between non-bonding electrons on the chlorine atoms overcome the lone pair-lone pair repulsion. Hence, the order of bond angle ${ClO}_{2} > {Cl}_{2} O > H_{2} O > {OF}_{2}$ .

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