First slide

13th group or boron group

Question

Correct order of bond angles for the following is

Moderate

A

${NH}_{3} > {PCl}_{3} > {BCl}_{3}$
B

${BCl}_{3} > {CH}_{4} > {PCl}_{3}$
C

${BCl}_{3} > {PCl}_{3} > {NH}_{3}$
D

${PCl}_{3} > {BCl}_{3} > {NH}_{3}$

Solution

BCl₃ is sp2 hybridized CH₄ is sp3 hybridized PCl₃ is sp³ hybridized.
As the character of p is more the bond angle of central atom is less.
However CH₄ and PCl₃ are having same p character but the lone pair on PCl₃ reduces the regular bond angle.
So the correct order is BCl₃>CH₄>PCl₃

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