The correct order of decreasing second ionisation enthalpy of Ti(22), V(23), Cr(24) and Mn(25) is
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a
Cr > Mn >V> Ti
b
V> Mn > Cr > Ti
c
Mn > Cr > Ti >V
d
Ti >V> Cr > Mn
answer is A.
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Detailed Solution
The second ionisation energies of the first transitions series increase almost regularly with increase in atomic number. However, the value for Cr is sufficiently higher than those of its neighbour, i. e., Mn this is due to stable configuration of Cr+ (3d5 exactly half-filled.)