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Q.

The correct order of the energy of molecular orbitals in a molecule having four electrons

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a

σ2s>σ2pz>σ2px

b

σ2s<π2px<σ2pz

c

σ 2s< σ 2pz = π 2px

d

σ2pz< σ2s< σ2px

answer is B.

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Detailed Solution

upto N2 the correct increases order of energies of various molecular orbitals is
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