Q.
The correct order of the energy of molecular orbitals in a molecule having four electrons
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a
σ2s>σ2pz>σ2px
b
σ2s<π2px<σ2pz
c
σ 2s< σ 2pz = π 2px
d
σ2pz< σ2s< σ2px
answer is B.
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Detailed Solution
upto N2 the correct increases order of energies of various molecular orbitals is
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