The correct order of ionic size of N3−,Na+,F−,Mg2+ and O2− is :

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Mg2+>Na+>F−>O2−

N3−O2−>Na+>Mg2+

Mg2+

N3−>O2−>F−>Na+

answer is C.

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Detailed Solution

N3−,Na+,F−,Mg2+ and O2− are isoelectronic species. All have 10 electrons. As pe↑; size decreases Mg2+

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