First slide

Aplicaitons of VBT

Question

The correct order of magnetic moments (spin values in B.M.) among is:

Moderate

A

${[Fe (CN)_{6}]}^{4 -} > {[{CoCl}_{4}]}^{2 -} > {[{MnCl}_{4}]}^{2 -}$
B

${[{MnCl}_{4}]}^{2 -} > {[Fe (CN)_{6}]}^{4 -} > {[{CoCl}_{4}]}^{2 -}$
C

${[Fe (CN)_{6}]}^{4} > {[{MnCl}_{4}]}^{2 -} > {[{CoCl}_{4}]}^{2 -}$
D

${[{MnCl}_{4}]}^{2 -} > {[{CoCl}_{4}]}^{2 -} > {[Fe (CN)_{6}]}^{4}$

Solution

Mn²⁺, Fe²⁺ and Co²⁺ has 3d⁵, 3d⁶ and 3d⁷ configurations having 5, 0 and 3 unpaired electrons respectively.

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