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a
N < C < P < S
b
C < N < P < S
c
N < C < S < P
d
C < N < S < P
answer is C.
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Detailed Solution
C and N are of 2nd period element. Size decreases from C to N. Therefore, size of N < C.P and S are of 3rd period elements. But size of P > S [opposite to the expected trend, i.e. size of S > P].Moreover, size of 3rd period elements is greater than that of 2nd period. Hence the correct order of sizes is P>S 3rd period >C>N 2nd period