First slide

Covalent Bonding

Question

The correct orders regarding bond length:

Moderate

A

$N_{2} H_{2} < N_{2} H_{4}$ (N – N Bond length)
B

$N O > N O^{+}$ (N – O Bond length)
C

$C_{2} H_{4} > K [P t C l_{3} (C_{2} H_{4})]$ (C – C Bond length)
D

$P O F_{3} > P O C l_{3}$ (P – O Bond length)

Solution

(A)
B) NO $N O^{+}$
BO=2.5 BO=3
C) Due to back bonding to p* orbital of $C H_{2} = C H_{2}$ is complex BO decreases hence bond length increases
D)
P-F (more P-character) Þ P–O (more S-character) Þ P–O bond length less P–Cl (less P-character) Þ P–O (Less S-character) Þ P–O bond length more

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