Q.

The correct relations showing Raoult's law are

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p∘−pp∘= molefractionofsolute

p∘−pp= molesofsolute molesofsolution

p∘−pp∘= molesofsolvent molesofsolute

For very dilute solution, p∘−pp∘= molesofsolvent molesofsolute

answer is A.

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Detailed Solution

According to Raoult's law, Relative lowering in vapour pressure = Mole fraction of solute p∘−pp∘=x2⇒p∘−pp∘=n2n1+n2or p∘p∘−p=n1+n2n2or p∘p∘−p=1+n1n2 p∘p∘−p−1=n1n2⇒pp∘−p=n1n2or p∘−pp=n2n1

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