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Q.

The correct relations showing Raoult's law are

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a

p∘−pp∘= molefractionofsolute

b

p∘−pp= molesofsolute  molesofsolution

c

p∘−pp∘= molesofsolvent  molesofsolute

d

For very dilute solution, p∘−pp∘= molesofsolvent  molesofsolute

answer is A.

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Detailed Solution

According to Raoult's law, Relative lowering in vapour pressure = Mole fraction of solute                                p∘−pp∘=x2⇒p∘−pp∘=n2n1+n2or                           p∘p∘−p=n1+n2n2or                          p∘p∘−p=1+n1n2                    p∘p∘−p−1=n1n2⇒pp∘−p=n1n2or                              p∘−pp=n2n1
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The correct relations showing Raoult's law are