Q.
The correct relations showing Raoult's law are
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a
p∘−pp∘= molefractionofsolute
b
p∘−pp= molesofsolute molesofsolution
c
p∘−pp∘= molesofsolvent molesofsolute
d
For very dilute solution, p∘−pp∘= molesofsolvent molesofsolute
answer is A.
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Detailed Solution
According to Raoult's law, Relative lowering in vapour pressure = Mole fraction of solute p∘−pp∘=x2⇒p∘−pp∘=n2n1+n2or p∘p∘−p=n1+n2n2or p∘p∘−p=1+n1n2 p∘p∘−p−1=n1n2⇒pp∘−p=n1n2or p∘−pp=n2n1
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