The correct relationship between standard free energy change in a reaction and the corresponding equilibrium constant K is
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a
-∆G0=RT ln K
b
∆G=RT ln K
c
-∆G=RT ln K
d
∆G0=R ln K
answer is A.
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Detailed Solution
A mathematical expression of the thermodynamic view of equilibrium can be described by :∆G=∆Go+RTlnKAt equilibrium, ∆G=0∴∆Go=-RTlnK∆Go=-2.303RTlogKWhere ∆Go is standard Gibbs energy change.