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An Intiative by Sri Chaitanya
a
σp−p > σs−p> σs−s > πp−p
b
σp−p > πp−p> σs−p > σs−s
c
σs−s > σs−p> σp−p > πp−p
d
σp−p > πp−p> σs−s > σs−p
answer is A.
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