The correct set of four quantum numbers for the valence electrons of rubidium atom (Z =37) is

Given, atomic number of Rb, Z = 37 Thus, its electronic configuration is [Kr]5s1. Since, the last electron or valence electron enter in 5s subshell.So, the quantum numbers are n = 5,l = 0, (for s-orbital)m=0(∵m=+l to -l),s=+1/2 or -1/2