The correct set of four quantum numbers for the valence electrons of rubidium atom (Z =37) is

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5,0,0,+12

5,1,0,+12

5,1,1,+12

5,0,1,+12

answer is A.

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Detailed Solution

Given, atomic number of Rb, Z = 37 Thus, its electronic configuration is [Kr]5s1. Since, the last electron or valence electron enter in 5s subshell.So, the quantum numbers are n = 5,l = 0, (for s-orbital)m=0(∵m=+l to -l),s=+1/2 or -1/2

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