The correct stability order of the following resonance structure is
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a
(I)> (II) > (IV) > (III)
b
(I)> (III) > (II) > (IV)
c
(II)> (I) > (III) > (IV)
d
(III)> (I) > (IV) > (II)
answer is B.
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Detailed Solution
I has maximum covalent bond and negative charge on electronegative nitrogen, most stable. III has more covalent bond than both II and IV, III is second most stable. Between II and IV, II is more stable since it has negative charge on nitrogen while IV has negative charge carbon.