First slide

Hydrogen

Question

The correct statement about the following is

Easy

A

In H₂ and D₂ the ratio of bond length is 1:2
B

₁H¹ can be used as a tracer
C

₁H³ emits low energetic β radiation and no γ radiations
D

₁H² has only two fundamental particles

Solution

B.L of H₂ ≈ D₂ ie., 1:1
₁H¹ can't be used as a tracer
₁H³ → ₁H³ + _-1e^o
β-ray [Low energetic] ${}_{1}^{2}H$
No. of protons = z =1 : A = Mass number = 2
No. of neutrons = A-z =2-1=1
No. of electrons =1
has 3 fundamental ${}_{1}^{2}H$ particles.

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