First slide

Gibb's Helmholtz equation

Question

The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

Easy

A

$ΔH < 0 and ΔS > 0$
B

$ΔH < 0 and ΔS < 0$
C

$ΔH < 0 and ΔS = 0$
D

$ΔH > 0 and ΔS < 0$

Solution

$ΔG = ΔH - TΔS$
$\begin{array}{l} If ΔH < 0 and ΔS > 0 \\ ΔG = (- ve) - T (+ ve) \end{array}$
$then at all temperatures, ΔG = - ve, spontaneous reaction .$
$If Δ H < 0 and Δ S = 0$
$Δ G = (- ve) - T (0) = - ve at all temperatures. O p t i o n 3 c a n a l s o b e c o n d i t i o n f o r s p o n \tan e i t y .$

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