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The correct thermodynamic conditions for the spontaneous reaction at all temperatures is

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By Expert Faculty of Sri Chaitanya
a
ΔH<0 and ΔS>0
b
ΔH<0 and ΔS<0
c
ΔH<0 and ΔS=0
d
ΔH>0 and ΔS<0

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detailed solution

Correct option is A

ΔG=ΔH-TΔS If ΔH<0 and ΔS>0ΔG=(-ve)-T(+ve) then at all temperatures, ΔG=-ve, spontaneous reaction.  If ΔH<0 and ΔS=0ΔG=(-ve)-T(0)=-ve at all temperatures.  Option 3 can also be condition for spontaneity.


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