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Q.

The cost of electricity required to deposit 1 g of Mg is Rs.5.00 .How much would it cost to deposit 10.0 g of Al?

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a

10.00 Rs

b

27.00 Rs

c

44.44 Rs

d

66.67 Rs

answer is D.

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Detailed Solution

IF→12g    Mg↓?→1g   Mg↓=112F:So F12=5RsIF→9g Al↓?→10g   Al↓   =109FF12→5 Rs10F9→?=10F×129×F×5 Rs=66.67Rs
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