In a CPS (Closed$$ Packed $$Structure) of mixed oxides, it is found that lattice has $$O2-$$ (oxide$$ $$ions) and $$one-half$$ of octahedral voids are occupied by trivalent cations (A3+) and $$one-eight$$ of tetrahedral voids are occupied by divalent cations (B2+). Based on derived formula of the mixed oxide the correct statements will be

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Number of octahedral voids per ion in lattice $$=$$ $$1Hence$$, number of trivalent cations (A3+)=1$$×$$12=12Number$$ of tetrahedral voids per ion in lattice $$=$$ $$2Hence$$, Number of divalent cations $$(B2+) $$=$$ $$2$$ × $$18=14Thus$$, formula is $$A1/2B1/4O$$ or $$A2BO4$$.

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