In a CPS (Closed Packed Structure) of mixed oxides, it is found that lattice has O2- (oxide ions) and one-half of octahedral voids are occupied by trivalent cations (A3+) and one-eight of tetrahedral voids are occupied by divalent cations (B2+). Based on derived formula of the mixed oxide the correct statements will be

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number of trivalent cations = ½

composition of oxide is A2BO4

number of dipositive cations = ¼

no. of tetrahedral voids are 4

answer is A.

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Detailed Solution

Number of octahedral voids per ion in lattice = 1Hence, number of trivalent cations (A3+)=1×12=12Number of tetrahedral voids per ion in lattice = 2Hence, Number of divalent cations (B2+) = 2 × 18=14Thus, formula is A1/2B1/4O or A2BO4.

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