First slide

Crystal lattices and unit cells

Question

A crystal has KCl type structure. In this crystal, shortest distance between a cation and anion is 200 pm. The volume of the unit cell is a × 10^-22 cm³. Value of a is

Moderate

Solution

$\begin{array}{l} a = 2 (r^{+} + r) \\ a = 2 \times 200 = 4 \times 10^{- 8} cm \\ Vol. of unit cell = a^{3} = {(4 \times 10^{- 8})}^{3} {cm}^{3} \\ = 64 \times 10^{- 22} {cm}^{3} \end{array}$

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