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A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8 g cm−3, then the number of atoms present in 256 g of the crystal is N×1024 . The value of N is

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answer is 2.

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Detailed Solution

FCC: Z=4d=Z×Ma3⋅NO8=4×( Mol. Wt)(400)3×10−123N0 mol.mass =2×400×10−123×N0 no.of moles =2×400×10−123×N0256 No.of atoms =2×400×10−123×N0256=2×N0

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