Questions
vs . Ered graph is of the type as shown in figure where OA = 0.34V, then electrode potential of the half-cell of Cu ;Cu2+ (0.1 M) will be:
detailed solution
Correct option is A
ECu/Cu2+=ECu/Cu2+∘−0.0592logCu2+If logCu2+=0 i.e. Cu2+=1then ECu/Cu2+=E0Cu/Cu2+or OA=ECu/Cu+2o=−ECu+2/Cu∘=−0.34Now, ECu/Cu2⋅=−0.34−0.0592log 0.1=−0.34+0.0592Similar Questions
The conductivity of a saturated solution of is at 25°C. Conductivity of water is . What is the approximate molar conductivity of ion at infinite dilution, given molar conductivity of Ag+ ions at infinite dilution is and
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