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Q.

For a cubic unit cell, the distance dhld between planes with Miller indices hkl is given bydhld2=a2h2+k2+l2where, a is the length of the cubic unit cell. d,,, spacing for crystalline K is 0.3078 nm. A wavelength of 0.533 nm falls on this place.The value of sin θ for first order reflection in Bragg's diffraction is

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a

1.00

b

0.284

c

0.87

d

0.71

answer is B.

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Detailed Solution

dhld2=a2h2+k2+l2∴a2=dhld2h2+k2+l2=(0.3078)212+12+12a=0.284nm.
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