The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion, the cation has smaller ionic radius. Choose the correct statement(s).

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

The empirical formula of the compound is MX.

The cation M and anion X have different coordination geometries.

The ratio of M-X bond length to the cubic unit cell edge length is 0.866.

The ratio of the ionic radii of cation M to anion X is 0.41

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

1) ZM=2×12=1ZX=4×14=1∴ Empirical formula is M2) Coordinate numbers of both M and X is 8.3) Bond length of M – X bond =AB=3⋅a2=0.866 a4) rM:rX=(3−1):1=0.732:1.000

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET

Get Expert Academic Guidance – Connect with a Counselor Today!

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET