A current of 9.65 ampere is passed through 0.2 M,500 mL aqueous solution of CuSO4 using Cu-electrode for 300 sec. than calculate [Cu2+] concentration in the resulting solution. If volume of solution remains constant:

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1 M

1.96 M

1.35 M

0.2 M

answer is D.

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Detailed Solution

E∘ oxidation CuCu2+>E∘H2OO2ER∘Cu2+Cu>ER∘H2OH2So equivalent of Cu oxidised at anode = equivalent Cu2+ reduced at cathode. So [Cu2+] = constant