First slide

Electrolysis

Question

A current of 9.65 ampere is passed through 0.2 M,500 mL aqueous solution of CuSO₄ using Cu-electrode for 300 sec. than calculate [Cu²⁺] concentration in the resulting solution. If volume of solution remains constant:

Easy

A

1 M
B

1.96 M
C

1.35 M
D

0.2 M

Solution

$\begin{array}{l} E^{\circ} oxidation Cu |{Cu}^{2 +} > E^{\circ} H_{2} O| O_{2} \\ E_{R}^{\circ} {Cu}^{2 +} |Cu > E_{R}^{\circ} H_{2} O| H_{2} \end{array}$
So equivalent of Cu oxidised at anode = equivalent Cu²⁺ reduced at cathode. So [Cu²⁺] = constant

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App