A current of 9.65 ampere is passed through 0.2 M,500 mL aqueous solution of CuSO4 using Cu-electrode for 300 sec. than calculate [Cu2+] concentration in the resulting solution. If volume of solution remains constant:
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a
1 M
b
1.96 M
c
1.35 M
d
0.2 M
answer is D.
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Detailed Solution
E∘ oxidation CuCu2+>E∘H2OO2ER∘Cu2+Cu>ER∘H2OH2So equivalent of Cu oxidised at anode = equivalent Cu2+ reduced at cathode. So [Cu2+] = constant