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CuSO4·5H2O(s)⇌CuSO4·3H2O(s)+2H2O(g);Kp=4×10-4 atm2 If the vapour pressure of water is 38 torr then percentage of relative humidity is : (Assume all data at constant temperature)

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a

4

b

10

c

40

d

None of these

answer is C.

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Detailed Solution

Kp=PH2O2=4×10-4atm2 PH2O=2×10-2 atm  Relative humidity=2×10-2×76038×100=40%
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