In a cyclic process, heat transfers are + 14.7 kJ, -25.2kJ, -3.56 kJ and + 31.5 kJ. What is the net work done in the net cyclic process?

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10 kJ

-10 kJ

-17.44 kJ

+17.44 kJ

answer is C.

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Detailed Solution

In the cyclic process ΔWcyc+Δqcyc=0 or ΔWcyclic =−Δqcyc =−[14.7−25.2−3.56+31.5] kJ or ΔWcyclic =−17.44kJ

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