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4d,5p,5f and 6p orbitals are arranged in the order of decreasing energy. The correct option is

5 f>6 p>4 d>5 p
5 f>6 p>5 p>4 d
6 p>5 f>5 p>4 d
6 p>5 f>4 d>5 p

detailed solution

Correct option is B

Higher the value of (n+l) for an orbital, higher is its energy. However, if two different types of orbitals have same value of (n+l) the orbital with lower value of n has lower energy. Therefore, decreasing order of energy of the given orbitals is 5 f5+3>6 p6+1>5 p5+1>4 d4+2.

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