First slide

Electrochemical cell

Question

Daniel cell is shown as

Easy

A

Zn_(s)/ Zn²⁺_(aq) // Cu_(s)/ Cu²⁺_(aq)
B

Zn_(s)/ Zn²⁺ _(aq) // Cu²⁺ _(aq)/Cu_(s)
C

Cu_(s)/ Cu²⁺ _(aq)// Zn²⁺ _(aq)/Cu_(s)
D

Cu²⁺_(aq) / Cu_(s)^//Zn²⁺_(aq)/ Zn_(s)

Solution

Daniel cell is constructured between Zn electrode (under standard conditions) and Cuelectrode (under standard conditions)
Zn oxides to Zn⁺² , Cu⁺² reduces to Cu
A Zn rod/sheet in contact with 1M ZnSO₄ is the anode
A Cu rod/sheet in contact with 1M CuSO₄ is the Cathode
$\large \begin{array}{*{20}{c}} {Anode\;:\;Zn(s)\; \rightleftharpoons \,Z{n^{ + 2}}(aq)\; + \;2\bar e} \\ {Cathode\;:\;C{u^{ + 2}}(aq)\; + \;2\bar e\; \rightleftharpoons \;Cu(s)} \\ {\overline {\underline {Zn(s)\; + \;C{u^{ + 2}}(aq)\; \rightleftharpoons \;Z{n^{ + 2}}(aq)\; + \;Cu(s)} } } \end{array}$
Cell notation
Zn(s)/Zn⁺²(1M)//Cu⁺²(1m)/Cu(s)

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