Q.

Daniel cell is shown as

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Zn(s) / Zn2+(aq) // Cu(s) / Cu2+(aq)

Zn(s) / Zn2+ (aq) // Cu2+ (aq) /Cu(s)

Cu(s) / Cu2+ (aq) // Zn2+ (aq) /Cu(s)

Cu2+(aq) / Cu(s)// Zn2+ (aq) / Zn(s)

answer is B.

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Detailed Solution

Daniel cell is constructured between Zn electrode (under standard conditions) and Cu electrode (under standard conditions)Zn oxides to Zn+2 , Cu+2 reduces to CuA Zn rod/sheet in contact with 1M ZnSO4 is the anodeA Cu rod/sheet in contact with 1M CuSO4 is the CathodeCell notationZn(s)/Zn+2(1M)//Cu+2(1m)/Cu(s)

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