Q.

The de Broglie wavelength of  an electron  in the  4th Bohr orbit is :

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a

2πa0

b

8πa0

c

4πa0

d

6πa0

answer is B.

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Detailed Solution

For 4th orbit rn=n2z×a0=421×a0=16a0For debroglie theory,nλ=2πrn⇒4×λ=2π*16a0λ=8πa0
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