For the decomposition of azoisopropane into hexane and nitrogen at 543 K, the following data is obtained.
${\left({\mathrm{CH}}_3\right)}_2\mathrm{CHN}=\mathrm{NCH}{\left({\mathrm{CH}}_3\right)}_2⟶{\mathrm{N}}_2+{\mathrm{C}}_6{\mathrm{H}}_{14}$

Experiment	Time (s)	Total pressure (mm Hg)
I	0	35.0
II	360	54.0

The rate constant at 360 is

detailed solution

Correct option is A

Let the initial pressure of azoisopropane is po and,after (r ) time, its pressure reduces by x.So,         CH32CHN=NCHCH32⟶N2+C6H14 At t=0    p0            0      0 After 360s     p0−x             x      xTotal pressure after 360s pt=p0−x+x+x=35+x=54                                            x=54−35=19mmHgx=19mmHgas,                                     p0=35mmHg  p0−x=35−19=16mmHgFor first order reaction,rate constant, (k)=2.303tlogp0p0−x                            =2.303360log3516=2.303360log2.187                            =2.303360×0.34=2.17×10−3s−1