Q.
For the decomposition of azoisopropane into hexane and nitrogen at 543 K, the following data is obtained.CH32CHN=NCHCH32⟶N2+C6H14The rate constant at 360 is
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a
2. 17×10−3s−1
b
3.25×10−3s−1
c
3.25×10−3min−1
d
1.98×10−3s−1
answer is A.
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Detailed Solution
Let the initial pressure of azoisopropane is po and,after (r ) time, its pressure reduces by x.So, CH32CHN=NCHCH32⟶N2+C6H14 At t=0 p0 0 0 After 360s p0−x x xTotal pressure after 360s pt=p0−x+x+x=35+x=54 x=54−35=19mmHgx=19mmHgas, p0=35mmHg p0−x=35−19=16mmHgFor first order reaction,rate constant, (k)=2.303tlogp0p0−x =2.303360log3516=2.303360log2.187 =2.303360×0.34=2.17×10−3s−1
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