Q.

For the decomposition of azoisopropane into hexane and nitrogen at 543 K, the following data is obtained.CH32CHN=NCHCH32⟶N2+C6H14The rate constant at 360 is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

2. 17×10−3s−1

b

3.25×10−3s−1

c

3.25×10−3min−1

d

1.98×10−3s−1

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Let the initial pressure of azoisopropane is po and,after (r ) time, its pressure reduces by x.So,         CH32CHN=NCHCH32⟶N2+C6H14 At t=0    p0            0      0 After 360s     p0−x             x      xTotal pressure after 360s pt=p0−x+x+x=35+x=54                                            x=54−35=19mmHgx=19mmHgas,                                     p0=35mmHg  p0−x=35−19=16mmHgFor first order reaction,rate constant, (k)=2.303tlogp0p0−x                            =2.303360log3516=2.303360log2.187                            =2.303360×0.34=2.17×10−3s−1
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon