Decomposition of NH3 on gold surface follows zero order kinetics. If rate constant K is 2×10−5M,s−1, rate of formation of N2 will be

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10−3M,s−1

2.5×10−4M,s−1

2×10−5M,s−1

10-5 M,s-1

answer is D.

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Detailed Solution

For zero order reaction r=k=constant 2NH3→1N2+3H2 (r1) (r2)rNH3=r1=K1NH30=K1=2×10-5rN2=r2=K2.NH30=K2=?r12=r21 and k12=k21k2=2×10-52=10-5

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