In the decomposition of $$PCl5$$, the degree of decomposition of $$PCl5$$ is $$0.5$$. If initially $$2$$ moles of $$PCl5$$ is taken in a $$2$$ litre vessel, the value of Kp at an equilibrium pressure of $$2$$ atm is

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In the decomposition of $$PCl5$$,  the degree of decomposition of $$PCl5$$  is $$0.5$$. If initially $$2$$ moles of  $$PCl5$$ is taken in a $$2$$ litre vessel,  the value of Kp at an equilibrium pressure of $$2$$ atm is

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Degree of decomposition $$=$$ $$0.5It$$ meansInitial moles                      Moles decomposed          $$1$$                                                   $$0.5$$         $$2$$                                                     ?Moles decomposed $$=$$ $$1$$                                           $$PCl5$$⇌    $$PCl3$$  $$+$$   $$Cl2Initial$$ moles                         $$2$$            $$0$$          $$0Moles$$ at eqbm.                (2$$–$$1)         $$1$$          $$1XPCl3$$  $$=$$  $$XCl2$$  $$=$$  $$XPCl5$$  $$=$$ $$13PPCl3$$  $$=$$  $$PCl2$$  $$=$$  $$PPCl5$$  $$=$$ $$2$$  ×$$13Kp=$$   $$PCl2$$  ×  $$PPCl3PPCl5$$ $$Kp=$$   $$23$$  ×  $$2323$$ $$=23$$  atm

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