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Q.

In the decomposition of PCl5,  the degree of decomposition of PCl5  is 0.5. If initially 2 moles of  PCl5 is taken in a 2 litre vessel,  the value of Kp at an equilibrium pressure of 2 atm is

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a

13 atm−1

b

13atm

c

23atm−1

d

23atm

answer is D.

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Detailed Solution

Degree of decomposition = 0.5It meansInitial moles                      Moles decomposed          1                                                   0.5         2                                                     ?Moles decomposed = 1                                           PCl5⇌    PCl3  +   Cl2Initial moles                         2            0          0Moles at eqbm.                (2–1)         1          1XPCl3  =  XCl2  =  XPCl5  = 13PPCl3  =  PCl2  =  PPCl5  = 2  ×13Kp=   PCl2  ×  PPCl3PPCl5 Kp=   23  ×  2323 =23  atm
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