For the decomposition reactionNH2COONH4(s)  ⇋ 2NH3(g) + CO2(g)The KP=2.9 × 10-5 atm3. The total pressure of gases at equilibrium when 1 mole of NH2COONH4(s) was taken to start with would be

NH2COONH4(s)  ⇋ 2NH3(g) + CO2(g)         1                             2                 1KP=2.9 × 10-5 atm3If the P is the total pressure at equilibriumKP=2p32  p3∴  P3=27×2.9×10-54=1.9575P=1.95753=0.058