Q.

Decrease in bond order of ligand is higher in :

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a

M⇄σπCO

b

M⇄σπN2

c

M⇆πPPh3

d

M⇄ππPF3

answer is B.

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Detailed Solution

(a) [MσπCO] In such complex CO donates electron pair from NBMO having slight ABMO character, so its sigma bond order increases.(b) M⟼πN2 such complex N2 donates electron pair from BMO, which results in more decrement of sigma bond order.
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