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a
M⇄σπCO
b
M⇄σπN2
c
M⇆πPPh3
d
M⇄ππPF3
answer is B.
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Detailed Solution
(a) [MσπCO] In such complex CO donates electron pair from NBMO having slight ABMO character, so its sigma bond order increases.(b) M⟼πN2 such complex N2 donates electron pair from BMO, which results in more decrement of sigma bond order.