The decreasing order of the first ionization energy in kJmol–1 of He, Mg and Na is He > Mg > Na. The increasing order of second ionization energy of these elements will be

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Na < Mg < He

Mg < Na < He

Mg < He < Na

Na < He < Mg

answer is C.

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Detailed Solution

IP1 of He>Mg>NaIP2 of Na>He>Mg (or) Mg

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