The decreasing order of -I effect of the orbitals is:I. sp II. sp2 III. sp3
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a
I > II > III
b
III > II > I
c
I > III > II
d
II > III > I
answer is A.
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Detailed Solution
The more the s character, the more is the penetration effect of s orbital towards the nucleus, and hence more e-withdrawing effect. So, sp (50%s) > sp2 (33%s) > sp3 (25%s).