The decreasing order of second ionisation potential of K, Ca, Ba is

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K > Ca > Ba

Ca > Ba > K

Ba > K > Ca

K > Ba > Ca

answer is A.

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Detailed Solution

IA [Mgas] ns1 →-e-+IE1[Inert gas(M+)] →-e-+IE2IIA[Mgas] ns2 →-e-+IE1 M+ →-e-+IE2 Inert gas[M+2]IE2 : IA > IIAReason :After removal of 1e- from IA group elements the formed M+ ion gets stable inert gas configuration.Therefore removal of 2nd electron from IA group elements is highly difficult and hence 2nd IE's of IA group elements are greater than that of IIA group elements IE2Therefore IE2 of K > Ca→ In IIA group from Be to Ba atomic size increases hence IE decreasesTherefore the overall 2nd I.E's order isK>Ca>Ba

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