The decreasing order of second ionization energy of K, Ca and Ba is
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a
Ca > Ba > K
b
Ba > K > Ca
c
K > Ca > Ba
d
K > Ba >Ca
answer is C.
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Detailed Solution
As we move down the group size increases and the electron experience less effective nuclear charge and IE decreases down the group. hence IE of Ca > BaIE2 of K > Ca , due to noble gas configuration of K+