Q.
Decreasing order of stability of O2,O2-,O2+and O22- is
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a
O22->O2->O2>O2+
b
O2>O2+>O22->O2-
c
O2->O22->O2+>O2
d
O2+>O2>O2->O22-
answer is D.
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Detailed Solution
O2(16):KKσ2 s2σ*2 s2σ2pz2π2px2=π2py2π*2px1=π*2py1 Bond order =12(8-4)=2O22-(18):KKσ2s2σ*2s2σ2pz2π2px2=π2py2π*2px2=π*2py2 Bond order =12(8-6)=1O2-(17):KKσ2s2σ*2s2σ2pz2π2px2=π2py2π*2px2=π*2py1 Bond order =12(8-5)=1.5O2+(15):KKσ2 s2σ*2 s2σ2pz2π2px2=π2py2π*2px1 Bond order =12(8-3)=2.5 As, bond order ∝ stability The decreasing order of stability isO2+>O2>O2->O22-
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