Q.

The degree of dissociation of Ca(NO3)2 in a dilute aqueous solution containing 7.0 g of salt per 100 g of water at 100oC is 70%. If the vapour pressure of water at 100oC is 760 mmHg, the vapour pressure of the solution is

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748.2 mmHg

1492.6 mmHg

373.2 mmHg

74.03 mmHg

answer is A.

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Detailed Solution

Moles of Ca(NO3)2=7164 present in 100.0 g of water Since dissociation is 70%, the total number of particles 7164×0.7×3=0.0896=nAlso, moles of solvent =10018=5.55=NApplying Raoult's lawpo−psolutionpo=nn+N760−ps760=0.0890.089+5.55 760−ps = 7600.0895.637 =760[0.0157] =11.99 ps=760−11.99=748.01 mmHg

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