Q.

The degree of dissociation of l2 molecule of 1000oC and under atmospheric pressure is 40% by volume. If the dissociation is reduced to 20% at the same temp. total equilibrium pressure on the gas is :

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1.57 atm

2.57 atm

3.57 atm

4.57 atm

answer is D.

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Detailed Solution

I2(g) ⇌ 2I-(g) t=0, 1mol 0 teq.; 1-x 2x n=1-x+2x=1+x Kp=PI-2PI2=2x1+xP21-x1+xP=4x21-x2P Kpat 40%dissociation=Kpat 20%dissociation 4(0.4)21-(0.4)2P=4(0.2)21-(0.2)2P' given, P=1atm. , P'=? on solving, P'=4.57atm.

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