First slide

Applications of Kohlraush law

Question

Degree of dissociation of 0.1M weak monoacidic base, BOH is $0.2$ . Molar conductance at infinite dilution of BOH is $360 mho {cm}^{2} {mole}^{- 1}$ . Molar conductance of decimolar BOH will be ------- $mho {cm}^{2} {mole}^{- 1}$

Moderate

Solution

$For weak electrolytes, α = \frac{λ_{c}}{λ_{0}}; Given α = 0.2, λ_{0} = 360 mho {cm}^{2} {mole}^{- 1} λ_{c} = (360 \times 0.2) mho {cm}^{2} {mole}^{- 1}$

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