Q.

Degree of ionization of 0.1 m aqueous NaCl is α1 . Degree of ionization of 0.1 m aqueous K3FeCN6 is α2. Both these solutions have the same boiling point when α1 : α2 is equal to

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3 : 1

1 : 3

2 : 3

3 : 2

answer is A.

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Detailed Solution

ΔTb=i Kb m;Given ΔTb is same , Kb always is a constant ∴i1m1=i2m2 but m1=m2=0.1 m Thus i1=i2 . . .(1) NaCln=2 : i1=1-α1+2α1=1+α1;....2 K3FeCN6n=4 : i2=1-α2+4α2=1+3α2.....3 substituting eq 2 and eq 3 in equation (1) 1 +α1=1+3α2 α1α2=3

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