First slide

Gibb's free energy , Cell potential, Equilibrium constant

Question

ΔG⁰ of Cu⁺_(aq) and Cu²⁺_aq respectively are +50 and +66 kJ/mole. Value of (ΔH⁰–TΔS⁰) for Cu⁺_aq → Cu²⁺_aq in kilo joules is

Easy

A

-16
B

+116
C

-116
D

+16

Solution

${ΔG}^{0} = {ΔH}^{o} - {TΔS}^{o}$
${ΔG}^{0} = \sum {ΔG}_{product}^{0} - \sum {ΔG}_{reactants}^{0}$
${ΔG}^{0} = {ΔG}_{Cu + 2}^{0} - {ΔG}_{{Cu}^{+}}^{0}$ $= 66 - 50 = + 16 K J$

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