The density in  g mL−1 of a 3.6 M sulphuric acid solution that is 29% H2SO4 (Molar mass = 98 g mol−1) by mass will be

Let the density of solution be ‘d’Molarity of solution given = 3.6Mi.e., 1 liter of solution contains 3.6 moles of H2SO4 or 1 liter of solution contain 3.6  ×  98  g of H2SO4  Since, the solution contains 29% by mass.100 g solution contains 29 g of H2SO4100d mL  solution  contains  29  g of H2SO41000 mL  solution  contains  3.6  ×  98  g of H2SO4 ∴    3.6  ×  98  =  29  ×  d100  ×  1000d=1.22Another method:                                 M=%by mass×10×dMolecular weight 3.6=29×10×d98 d=3.6×9829×10=1.22 g/ml